RE: TITAN 4B R/B Drag

From: Brierley David (DMBRIERLEY@dera.gov.uk)
Date: Mon Aug 21 2000 - 04:13:16 PDT

  • Next message: Paul Gabriel: "Lac4 obs 21 aug 00234.4"

    Don
    
    > From OIG:
    > 
    > TITAN 4B R/B
    > 1 26474U 00047B   00231.57370545 -.00031242  00000-0 -37706-2 0    64
    > 2 26474  68.0035  37.3934 0073700 180.4866 179.6211 14.81757829    94
    > TITAN 4B R/B
    > 1 26474U 00047B   00231.43870286  .00003711  00000-0  46107-3 0    59
    > 2 26474  68.0035  37.7569 0073521 180.6366 179.4680 14.81780383    77
    > TITAN 4B R/B
    > 1 26474U 00047B   00231.23619729  .00182905  00000-0  21515-1 0    46
    > 2 26474  68.0051  38.2980 0073813 180.7414 179.3378 14.81804695    40
    > TITAN 4B R/B
    > 1 26474U 00047B   00231.16869596  .00140906  00000-0  16661-1 0    37
    > 2 26474  68.0124  38.4601 0074870 181.2660 178.8231 14.81775241    31
    > TITAN 4B R/B
    > 1 26474U 00047B   00231.10119508  .00339667  00000-0  39096-1 0    22
    > 2 26474  68.0156  38.6306 0074902 181.2713 178.8208 14.81760028    25
    > 
    > How does a Titan 4B R/B get a negative drag term?   Is this a fuel
    > dump?
    > 
    I doubt it.  I think the answer must be that the orbits are computed
    automatically, with limited or no rejection of faulty observations.  My
    orbital analysis program has the capability to reject faulty
    observations, but I often find that I have to weed them out by trial and
    error.
    
    Where it's important to have an accurate orbit, I have a procedure for
    producing a smoothed elset from a series of OIG elsets.
    
    David.
    
    David M Brierley
    Malvern, Worcestershire, UK
    Station 2675, 52.1358N 2.3264W 70m
    
    
    
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