This formula is of little help in the current discussion, since as it stands the quantity C simply represents the relative brightness, for which we want to find a formula from the known angles. (If C is 0.1, the magnitude is +2.5 from its maximum 100% value, which is trivial) The known angle is usually sun-satellite-observer ( 0 at full phase) or sun-observer-satellite (180 degrees at full phase), and the standard magnitude is for 90 degrees (SkyMap) or full-phase (QuickSat) > > For example, let's say a new satellite is observed at magnitude > > +5.0 at precisely 1000-km slant range (to remove range from > > the equation), and 75% "illumination", which I take to mean > > a sun-satellite-observer angle of 45 degrees. What is this > > satellite's standard magnitude? (The correct answer is +5.94). > > According to the formula > A - 15.75 + 2.5 x log (BxB/C), > If I input 5.94 for A, 1000km for B, and 75% for C, I get +5.50. > Conclusions? ----------------------------------------------------------------- Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org http://www2.satellite.eu.org/seesat/seesatindex.html
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