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Sorry for the off topic posting, but I thought someone might be able to confirm or correct me on this. I'm trying to work out the semi-major Axis of the ISS. I've got an eccentricity of .0009604 and a mean motion of 15.71470012 n = 0.00114280524190645 (radians per second from the mean motion) GM = 398600.4418 (Geocentric gravitational constant) orbitalRadius = cuberoot (GM / n^2) = approx 6732.8 metres Using the above formula is this orbital Radius actually the semi-major axis?? I've been pulling my hair out looking through Keplers equations and still not confident I'm right. John ------------------------------------------------------------------------- Subscribe/Unsubscribe info, Frequently Asked Questions, SeeSat-L archive: http://www.satobs.org/seesat/seesatindex.html

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