# Re: More GEO questions

From: billm (escape@velocity.net)
Date: Fri Oct 12 2001 - 10:23:40 EDT

• Next message: Patrick McNally: "Re: More GEO questions II"

```> You've the miles and km the wrong way around.
> 1 mile = 1.612 km
> So 22,300 miles = 35,947.6 km (geostationair) and 60,000 miles = 96720 km

MAJOR OOPS!
Sorry.  But the question still remains.

Using the formula:
v = 2 pi x (radius of Earth + alt of sat)/period
v = 2 x 3.1416 x (3,963 mi + 22,300 mi)/24 hr

My spreadsheet tells me at an altitude of 60,000 miles (96720km) a satellite
needs to cruise at 16,745 mph (26993kph) to remain geostationary. What would
happen to this orbit?  Is it possible to remain geostationary out there?  I
realize it would be very inefficient, but is it possible?

Thanks,
Bill

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