Re: Mir reentry video

From: Tony Beresford (
Date: Sat Mar 24 2001 - 01:19:32 PST

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    At 18:15 24/03/01 , Tony Beresford wrote:
    > The answer is about 2 minutes
    >from 20 degrees elevation to 20 degrees elevation thru the zenith.
    A minor glitch its actually about 1 minute.
    My explanation of the calculation should perhaps be rewritten as
    >One just calculates the great circle distance to an object at an elevation
    >of 20 degrees and a height of 90 Km. double this answer, and calculate
    the fraction of the orbit that this represents, multiply
    by the orbital period ( 87 minutes say) to get the answer.
    The approximations involved can only possibly affect 
    the answer by 1 in the 2nd significant figure.
    Tony Beresford
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