FORGET that solution. 52.33 is obviously wrong. The maths were probably essentially correct, but I think I swapped x and y somewhere in the chain. I don't have time to sort that out today. Another way (a combination of trigonometry and vector arithmetic) gave fewer steps to follow, and shorter end formulae. For very low orbits the limit is 45 degrees, 1.12 Earth radii gives 41.76, 1.15 --> 41.01, 1.18 --> 40.28 and for extreme values it tends to 1/a radians. /Björn ----- Original Message ----- From: "Björn Gimle" > Purely algebraic, I got 41.76 degrees. > > For 1.18 Earth radii, I get 52.33 degrees. > > For extreme accuracy, the cosine theorem should be used instead of vector > projections. > ----------------------------------------------------------------- To unsubscribe from SeeSat-L, send a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@satobs.org List archived at http://www.satobs.org/seesat/seesatindex.html
This archive was generated by hypermail 2b29 : Thu Oct 16 2003 - 15:38:51 EDT